A proton moves straight upward (away fromthe ground) through a uniform magnetic fieldthat points from east to west and has a mag-nitude of 5.9 T. If the proton moves with a speed 3.6×107m/s through this field, what is the magnitudeof the force acting on it? The charge on aproton is 1.60×10−19.Answer in units of N

pe = weightxheight = 2000x1000=2,000,000joules

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.

elctricity and magnet is conversion to it