A bicyclist is riding to the left with a velocity of 14 \,\dfrac{\text m}{\text s}14 s m 14, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction. After a steady gust of wind that lasts 3.5\,\text s3.5s3, point, 5, start text, s, end text, the bicyclist is moving to the left with a velocity of 21\,\dfrac{\text m}{\text s}21 s m 21, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction. Assuming the acceleration is constant, what is the acceleration of the bicyclist?

-2.0 m/s²

Explanation:Acceleration is the rate of change of velocity.

\begin{aligned}a&=\dfrac{\text{Change in velocity}}{\text{Change in time}}\\ \\ &=\dfrac{v_f-v_i}{\Delta t} \end{aligned}

a

=

Change in time

Change in velocity

=

Δt

v

f

−v

i

Hint #22 / 3

We can calculate the bicyclist's acceleration from the final velocity v_fv

f

v, start subscript, f, end subscript, initial velocity v_iv

i

v, start subscript, i, end subscript, and time interval \Delta tΔtdelta, t.

\begin{aligned}a&=\dfrac{v_f-v_i}{\Delta t}\\ \\ &=\dfrac{-21\,\dfrac{\text m}{\text s}-(-14\,\dfrac{\text m}{\text s})}{3.5\,\text s}\\ \\ &=-2.0\,\dfrac{\text m}{\text s^2}\end{aligned}

a

=

Δt

v

f

−v

i

=

3.5s

−21

s

m

−(−14

s

m

)

=−2.0

s

2

m

Hint #33 / 3

The acceleration of the bicyclist is -2.0\,\dfrac{\text m}{\text s^2}−2.0

s

2

m

minus, 2, point, 0, start fraction, start text, m, end text, divided by, start text, s, end text, squared, end fraction.

the answer is false. this is because for ice to melt, it requires latent heat of melting. latent heat means heat energy required to change phase without any increase in temperatures. therefore, the ice will take energy from the environment to melt hence atmospheric temperatures will reduce.