Physics, 20.03.2020 06:47 Fireburntbudder

A particle (charge 7.5 µC) is released from rest at a point on the x axis, x = 10 cm. It begins to move due to the presence of a 2.0-µC charge which remains fixed at the origin. What is the kinetic energy of the particle at the instant it passes the point x = 1.0 m? Group of answer choices 1.8 J 1.2 J 2.4 J 1.4 J 3.0 J

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Answer from: gooby1324

1.2 J

Explanation:

First of all, we have to take into account that at the beginning all energy is electrostatic potential

Ep = K*q1*q2/r = Et "total energy"

where r is the distance between charges. The total energy must conserve, hence, if we calculate the potential energy for x = 1.0 cm = 0.1 m, we can find the kinetic energy by subtracting the potential energy for x = 1.0m from the initial potential energy. In other words:

The energy for x = 0.1m is the total energy

Et = Ep = 8.98*10^(9)*7.5*10^(-6)*2.0*10^(-6)/0.1 = 1.35 J

The potential energy for x=1m

Ep' = 8.98*10^(9)*7.5*10^(-6)*2.0*10^(-6)/1 = 0.135 J

The kinetic energy is:

Et = Ep' + Ek

Ek = Et - Ep = 1.35 J - 0.135 J = 1.21 J ≅ 1.2 J

Answer from: Quest

answer: the correct answer is 1.

explanation: there are various process in which a radioactive nuclei decays:

1) alpha decay: in this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. the mass number is reduced by 4 units.

$_a^z\textrm{x}\rightarrow _{a-2}^{z-4}+_2^4\alpha$

2) electron capture: in this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. simply, a proton and an electron combines together to form a neutron. mass number does not change in this process.

$_a^z\textrm{x}+_{-1}^0\textrm{e}\rightarrow _{z-1}^a\textrm{y}$

3) gamma ray emission: it is a decay process in which an unstable nuclei gives excess energy by a spontaneous electromagnetic process. this decay releases $\gamma -radiations$ . this process does not change the mass number.

$_a^z\textrm{x}^*\rightarrow _a^z\textrm{x}+_0^0\gamma$

4) positron emission: it is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. this is also known as $\beta ^+$ -decay. in this the mass number remains same.

$_a^z\textrm{x}\rightarrow _{z-1}^a\textrm{y}+_{+1}^0e$

from the above information, we see that only alpha-decay is producing a change in the mass number of the nucleus.

Answer from: Quest

The objects do not reach terminal velocity there is not enough time from the time the object falls from when it hits the ground to achieve terminal velocity. an object must be placed higher to achieve terminal velocity in order to be in free fall.

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A particle (charge 7.5 µC) is released from rest at a point on the x axis, x = 10 cm. It begins to m...

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