The charge that passes through the filament of a certain light bulb in 5.00 s is 3.0 C. a. What is the current in the light bulb? b. How many electrons pass through the filament of the light bulb in a time interval of 1.0 min?

(a) I = 0.6 A

(b) 22.5 * 10^19 electrons

Explanation:

Parameters given:

(a) Current is given as the time Tate of charge flow. Mathematically,

I = Q/t

Charge, Q = 3 C

Time, t = 5 secs

I = 3/5 = 0.6A

(b) The current flowing through the filament is 0.6A. In 1 min (60 secs), the charge will be:

Q = I*t

Q = 0.6 * 60 = 36 C

An electron has a charge, Qe, of 1.6022 * 10^(-19) C. Hence, the number of electrons will be:

N = Q/Qe

N = 36/(1.6022 * 10^(-19))

N = 22.5 * 10^19 electrons

the first step is making objective observations.

they have to be based on a certain event and can be confirmed by others if it is right or not.

report!

explanation:

physics means: "the branch of science concerned with the nature and properties of matter and energy. the subject matter of physics, distinguished from that of chemistry and biology, includes mechanics, heat, light and other radiation, sound, electricity, magnetism, and the structure of atoms."