A 11.1 cm 11.1 cm long solenoid contains 703 turns 703 turns and carries a current of 4.31 A 4.31 A . What is the strength B B of the magnetic field at the center of this solenoid?

Explanation:

Given that

Length of solenoid

L=11.1cm = 0.111m

Number of turns

N=703turns

Current

I=4.31A

B=?

Thus, the magnetic field in the core of a solenoid is directly proportional to the product of the current flowing around the solenoid and the number of turns per unit length of the solenoid

B=μo•n•I

Where,

μo is constant and has a value of

μo=4π×10^-7

n is number of turn per unit length

n=N/L

n=703/0.111 = 6333.333 turns/m

I is the current, and it is 4.31A in this case

Then,

B=μo•n•i

B=4π×10^-7×6333.333×4.31

B=0.0343T

B=34.3mT

The magnetic field at the center of the coil is 34.3mT

Given Information:  

Current = I = 4.31 A  

Number of turns = N = 703

Length of solenoid = L = 11.1 cm = 0.11 m

Required Information:  

Magnetic field = B = ?

Magnetic field = 0.346 T

Step-by-step explanation:  

The magnetic field (B) produced in a current (I) carrying long solenoid of length (L) is given by

B = μ₀NI/L

Where μ₀ is the permeability of free space  and its value is 4πx10⁻⁷ T.m/A

B = (4πx10⁻⁷*703*4.31)/*0.11

B = 0.0346 T

Therefore, a magnetic field of strength 0.0346 T would be produced at the center of this solenoid.

in simple terms, the principle states that the buoyancy force on an object is equal to the weight of the fluid displaced by the object, or the density of the fluid multiplied by the submerged volume times the gravitational acceleration, g. this is also known as upthrust.