A spring has a natural length of 8 in. If it takes a force of 10 lb to compress the spring to a length of 6 in., how much work is required to compress the spring from its natural length to 7 in.

Required workdone is 5 lb.in

Explanation: Force acting on a spring is given by the relation,

F = -Kx

Here, K is the spring constant

x is the compression or expansion in spring

- Ve sign shows the direction of spring force is opposite to the externally applied force.

Natural length of spring = 8 inches

For final position of spring after compression = 6 inches

Force required to compress the spring by 2 inches (8 - 6 inches) is 10 lb

F = -Kx

10 = -K 2

K = 5 lb/in  

If the final position is 7 in i.e. compression by 1 in (8 - 7 in)

F = -Kx = - 5 1 = - 5 lb  (-Ve sign shows the direction of spring force is outward)

Work done = Force Displacement

WD = 5 1 = 5 lb.in

speed

ratio of distance traveled to time interval

net force

vector sum of forces on object

object

source of diverging light rays either luminous or illuminated

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explanation:

electromagnetic shielding is the practice of reducing the electromagnetic field in a space by blocking the field with barriers made of conductive or magnetic materials. shielding is typically applied to enclosures to isolate electrical devices from their surroundings, and to cables to isolate wires from the environment through which the cable runs. electromagnetic shielding that blocks radio frequency electromagnetic radiation is also known as rf shielding.

the shielding can reduce the coupling of radio waves, electromagnetic fields and electrostatic fields. a conductive enclosure used to block electrostatic fields is also known as a faraday cage. the amount of reduction depends very much upon the material used, its thickness, the size of the shielded volume and the frequency of the fields of interest and the size, shape and orientation of apertures in a shield to an incident electromagnetic

from wikipedia