The drawing shows a type of flow meter that can be used to measure the speed of blood in situations when a blood vessel is sufficiently exposed (e. g., during surgery). Blood is conductive enough that it can be treated as a moving conductor. When it flows perpendicularly with respect to a magnetic field, as in the drawing, electrodes can be used to measure the small voltage that develops across the vessel. Suppose the speed of the blood is 0.57 m/s and the diameter of the vessel is 5.4 mm. In a 0.73-T magnetic field what is the magnitude of the voltage that is measured with the electrodes in the drawing?

The image is missing and i have attached it;

Magnitude of Voltage = 2.21 x 10^(-3) V

Explanation:

From the question, The blood flowing at a speed v corresponds to the moving rod, and the diameter of the blood vessel corresponds to the length L of the rod in the figure. The magnitude of the magnetic

field is B, and the measured voltage is the emf (ξ) induced by the motion. Thus, we can apply;

ξ = BvL

Diameter L =5.4mm = 5.4 x 10^(-3)m

Thus;

ξ = 0.73 x 0.56 x 5.4 x 10^(-3) = 2.21 x 10^(-3) V

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