Physics, 19.03.2020 08:05 bankrollbaby01

The ac generator in a series RCL circuit has an rms voltage of 70.9 V. The values of the resistance, capacitive reactance, and inductive reactance are, respectively, R = 30.0 Ω, XC = 50.0 Ω, and XL = 90.0 Ω. What is the rms current in the circuit?

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Answer from: erinwebsterrr

The RMS current in the circuit is 1.418 A

Explanation:

The equation of the impedance of an RCL circuit is equal to:

Z = (R^2 + (XL - XC)^2)^1/2

Z = (30^2 + (50-90)^2)^1/2 = 50 ohms

To calculate the RMS current we must use Ohms' law, therefore:

I = V/Z = 70.9/50 = 1.418 A

Answer from: ryndersava

1.418 A

Explanation:

From Alternating current,

V = IZ Equation 1

Where V = rms Voltage, I = rms current, Z = Impedance of the RLC circuit.

make I the subject of the equation

I = V/Z Equation 2

But,

Z = √[(XL-Xc)²+R²] Equation 3

Where XL = inductive reactance, Xc = capacitive reactance, R = resistance

Substitute equation 3 into equation 2

I = V/√[(XL-Xc)²+R²] Equation 4

Given: V = 70.9 V, XL = 90 Ω, Xc = 50 Ω, R = 30 Ω

I = 70.9/√[(90-50)²+30²]

I = 70.9/√(40²+30²)

I = 70.9/√(1600+900)

I = 70.9/√2500

I = 70.9/50

I = 1.418 A

Answer from: Quest

answer: the correct answer is 1.

explanation: there are various process in which a radioactive nuclei decays:

1) alpha decay: in this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. the mass number is reduced by 4 units.

$_a^z\textrm{x}\rightarrow _{a-2}^{z-4}+_2^4\alpha$

2) electron capture: in this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. simply, a proton and an electron combines together to form a neutron. mass number does not change in this process.

$_a^z\textrm{x}+_{-1}^0\textrm{e}\rightarrow _{z-1}^a\textrm{y}$

3) gamma ray emission: it is a decay process in which an unstable nuclei gives excess energy by a spontaneous electromagnetic process. this decay releases $\gamma -radiations$ . this process does not change the mass number.

$_a^z\textrm{x}^*\rightarrow _a^z\textrm{x}+_0^0\gamma$

4) positron emission: it is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. this is also known as $\beta ^+$ -decay. in this the mass number remains same.

$_a^z\textrm{x}\rightarrow _{z-1}^a\textrm{y}+_{+1}^0e$

from the above information, we see that only alpha-decay is producing a change in the mass number of the nucleus.

Answer from: Quest

To use anything transparent

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The ac generator in a series RCL circuit has an rms voltage of 70.9 V. The values of the resistance,...

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