A uniform linear charge density of 4.0nC/m is distributed along the entire x axis. Consider a spherical(radius = 5.0 cm) surface centered on the origin. Determine theelectric flux through this surface.

1. 79 N · m2/C

2. 45 N · m2/C (what i think itis)

3. 68 N · m2/C

4. 62 N · m2/C

5. 23 N · m2/C (what the reply said itwas)

Ф = 45 N m² / C

Explanation:

For this exercise we use Gauss's law

        Ф = E .dA = qint / ε₀

        A = 4π r²

        Ф = E 4π r² = qint /ε₀  

Since the charge is along the x axis the linear charge density

         λ = q / x

         q = λ x

The charge inside the Gaussian surface is the charge on the line from x = -5 cm to x = 5 cm, so x_total = 10 cm

        Φ = λ x_total / ε₀  

Let's calculate

       Φ = 4.0 10⁻⁹ 0.10 / 8.85 10⁻¹²

       Ф = 45 N m² / C

- measure reactants precisely. ( first choice)

- stir to the reaction take place. ( second choice)

- wait patiently until the reaction completes. ( fourth choice)

- make sure to recover as much copper as possible. ( last choice)

the device is called “ rocket engine”