Wo charges -72 microcoulomb and +83 microcoulomb if the distance between them is 0.75m. Find the force of attraction.

Correct  Fc = 95.6 N

Explanation:

Fc = k q₁ q₂ / r² Coulomb force

where it was given:

k = 9 · 10⁹ N m²/C² dielectric constant,

q₁ = - 72 μC = - 72 · 10⁻⁶ C

q₂ = + 83 μC = + 83 · 10⁻⁶ C

r = 0.75 m = 75 · 10⁻² m   distance between charges

Since the given charges are opposite between them exist force of attraction.

Fc = k q₁ q₂ / r² = 9· 10⁹ ·  72 · 10⁻⁶ · 83 · 10⁻⁶ / (75 · 10⁻²)²

Fc = 53,784 · 10⁻³/ 5,625 · 10⁻⁴ = 9.56 · 10⁻³ · 10⁴ = 9.56 · 10 = 95.6 N

Fc = 95.6 N

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