A 10kg object experiences a horizontal force which causes it to accelerate 5 m/s2 moving it a distance of 20 m horizontally. How much work is done by the force

The work done by the force is 1000 J.

Explanation:

Given:

Mass of object (m) = 10 kg

Acceleration of the object (a) = 5 m/s²

Displacement of the object (S) = 20 m

Using Newton's second law, we have:

Force = Mass × Acceleration

Plug in the given values and solve for force 'F' acting on the object. This gives,

Now, work done by the force 'F' is equal to the product of force 'F' and the displacement it cause in its direction which is 20 m.

Therefore, the work done by the force is given as:

Work = Force × Displacement

Plug in the values given and solve for 'W'. This gives,

Therefore, the work done by the force is 1000 J.

spare some change and give it to the poor

explanation:

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find the sum of the two horizontal vectors and the sum of the two vertical vectors

isoceles right angled triangle