I need help with this assignment, I am mostly confused on part 2, I got part 1.

75 points, and first answer that's correct gets brainliest.

1. 0.4 m/s

2. 1.4875 m/s

Explanation:

1.

Following the law of conservation of momentum, the initial sum of momentum equals the final sum of momentum. Usually, momentum, p=mv where m represent mass and v is the velocity.

Here subscripts 1 and 2 for mass are for ball and table respectively while for velocity, 1 and 2 are the initial velocities of ball and table respectively, 3 and 4 are final velocities of ball and table respectively.

Substituting mass of ball with 0.2 kg while table with 3 kg, since the table is initially at rest then its initial velocity is zero. Also, the initial velocity of ball we substitute with 14 m/s and final velocity of the ball we substitute with 8 m/s then numerically it will be

2.

tex]m_1v_1+m_2v_2= m_1v_3 +m_2v_4[/tex]

Here subscripts 1 and 2 for mass of astronat and space junk respectively while for velocity, 1 and 2 are the initial velocities of astronaut and space junk respectively, 3 and 4 are final velocities of astronaut and space junk respectively.

Substituting mass of astronaut with 80 kg while space junk with 7 kg, since the astronaut is initially at rest then its initial velocity is zero. Also, the initial velocity of space junk we substitute with 11 m/s and final velocity of the space junk we substitute with -6 m/s then numerically it will be

most voltage drop calculators want the distance between the source and destination. then internally, they double it so both the source and return wires are calculated. but you need to know which distance the calculator uses so you're not half of what you should be or double what you should be.

most circuit breakers will not take a #6 directly, so the electrician will have to splice on a smaller pigtail. you also have to upsize the grounding wire when you upsized the ungrounded (hot) wire (see note in 250.122). this will preclude using most cable assemblies, as a cable with #6 copper will most likely only have a #10 grounding conductor. you need a #6 grounding conductor if the circuit is 20a. a #8 cable is no better, as it will have a #10 grounding conductor too. but most 20a breakers will take a #8 directly.

in your related post, you didn't say what type of load this is. if it is a light or heater, voltage drop won't be a big issue. if this is a motor, the current needs are huge at startup and the voltage drop can pose a problem. if this is a motor, knowing if the motor is under much load during startup will answer the voltage drop effect (a saw is easier to start than a compressor).

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