A rocket, which is in deep space and initially at rest relative to an inertial reference frame, has a mass of 60.4 × 105 kg, of which 3.51 × 105 kg is fuel. The rocket engine is then fired for 380 s, during which fuel is consumed at the rate of 490 kg/s. The speed of the exhaust products relative to the rocket is 2.36 km/s. (a) What is the rocket's thrust? After the 380 s firing, what are (b) the mass and (c) the speed of the rocket?

a The rocket's thrust is

b The mass of the rocket

c  The speed of the rocket

Explanation:

From the question we are told that

            The mass of Rocket  is  

             The mass of fuel is

            The duration the rocket engine was fired  

            The rate at  which fuel was consumed

  The speed of the exhaust product is  

Generally Thrust can be  represented as

   Substituting values

  The mass of fuel consumed in 380 s would  be

                 Rate of  fuel consumption * The the time taken (The duration the rocket engine was fired)

               =  490 × 380 = 186200 kg

  So the new mass of rocket would be

Generally velocity of a rocket can be mathematically represented as

where is the speed of the exhaust

            is the initial mass of the rocket

          is the final mass of the rocket

1= 26.17

2= 1.17

3=30.86

4=5.86

just took the assigment on edge

answer: 802.3 kilo joules of energy represents 191.75 kilo calorie of energy.

explanation:

energy released during combustion of one mole methane = 802.3 kilo joules

if 1 kilo joule = 0.239006   kilo calorie

then ,802.3 kilo joule will be = 802.30.239006 kilo calorie

802.3 kilo joule = 191.75 kilo calorie

hence, the energy in kilo calorie is 191.75 kilo calorie.