A new planet has been discovered that has a mass one-sixth that of Earth and a radius that is six times that of Earth. Determine the free fall acceleration on the surface of this planet. Express your answer in the appropriate mks units.

0.045 m/s²

Explanation:

Let the mass of Earth be 'M' and radius be 'R'.

Given:

Mass of the new planet (m) = one-sixth of Earth's mass =

Radius of new planet (r) = 6 times Earth's radius =

We know that, acceleration due to gravity of a planet of mass 'M' and radius 'R' is given as:

Now, this is acceleration due to gravity on Earth.

Now, acceleration due to gravity of new planet is given as:

Now, the value of 'g' on Earth is approximately 9.8 m/s². So,

Therefore, the free fall acceleration on the surface of this planet is 0.045 m/s².

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