In a simple RC circuit, at t=0 the switch is closed with the capacitor uncharged. If C=30µF, =50V and R=10k, what is the potential difference across the capacitor when I=2.0mA? At what rate is energy being stored in the capacitor when I = 2.0mA?

The potential difference across the capacitor is 30V and the rate is energy being stored in the capacitor is 0.06W

I = 2 mA and R = 10000 ohm, V = 50V, C=30µF

Hence voltage across resistor ():

= IR = 2 * 10⁻³ * 10000 = 20V

The voltage across capacitor () is:

The energy (U) stored in a capacitor is:

The potential difference across the capacitor is 30V and the rate is energy being stored in the capacitor is 0.06W

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Voltage across the capacitor is 30 V and rate of energy across the capacitor is 0.06 W

Explanation:

As we know that the current in the circuit at given instant of time is

i = 2.0 mA

R = 10 k ohm

now we know by ohm's law

so voltage across the capacitor + voltage across resistor = V

Now we know that

here rate of change in energy of the capacitor is given as

answer: electrons

double the distance = divide strength by 4