A 7.0 m ordinary lamp extension cord carries a current, I = 7.0 A. Such a cord typically consists of two parallel wires carrying equal currents in opposite directions. The two wires are separated by about 4 mm. Find the magnitude and direction of the force that the two segments of this cord exert on each other. A) 2 N , The wires repel B) 2 N, The wires attract C) 0.02 N , The wires repel D) 0.02 N, The wires attract

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.