Than to lift it straight up.
ROPE CLIMBING (2011;3 - AS90940)
A girl of mass 60 kg uses 5 100 J of energy when she climbs a vertical rope.
(a)
Calculate the maximum height it would be possible for the girl to reach.
(b)
In reality, the girl reaches a height of only 8 m.
Explain why the energy used by the girl during the climb does not equal the
work she does to reach the vertical height of 8 m.
In your answer you should:
name the type of energy the girl has when she is 8 m above the ground
calculate the work done to reach a height of 8 m above the ground
calculate the difference between the work done and the energy used by the
girl
•
explain where the "missing" energy has gone, and why this occurs.

Explanation:

(a) PE = mgh

5100 J = (60 kg) (10 m/s²) h

h = 8.5 m

(b) At 8 m, the girl has a gravitational potential energy of:

PE = mgh

PE = (60 kg) (10 m/s²) (8 m)

PE = 4800 J

The difference in energy is 300 J.  This energy is converted into heat in the girl's muscles.

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .

answera compound;