A 143-g sample of mercury is at an initial temperature of 25 °C. If 1067 joules of heat are applied to the sample, what is the final temperature of the mercury? The specific heat capacity of mercury is 0.14 J/(g∙ °C).

T = 78.3 °C

Explanation: To solve for the final temperature we will use the formula for heat which is Q = mc∆T, where ∆T is expressed as ( Final Temperature - Initial Temperature ). We will derive the formula to find Final temperature. So the working equation will be the following.

T = ( Q / mc ) + Ti

= 1067 J / 143 g (0.14 J/g°C) + 25°C

= 78.3 °C

i think it's 35 meters

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