A 9.5-kg monkey is hanging by one arm from a branch and is swinging on a vertical circle. As an approximation, assume a radial distance of 75 cm between the branch and the point where the monkey's mass is located. As the monkey swings through the lowest point on the circle, it has a speed of 2.2 m/s. a) the magnitude of the centripital force acting on the monkey. b) the magnitude of the tension in the monkey's arm.

(a) The centripetal force equals 61.31 Newtons

(b) The tension in the monkey's arm is equal to 154.51 Newtons

Explanation:

The equation for centripetal force is:

Here, m = 9.5 kg

V = 2.2 m/s

and r = 0.75 m

(a) Calculating the centripetal force using this equation we get:

(b) To calculate the tension in the monkey's arm we need to remember that the arm has to take the weight of the monkey AND resist the centrifugal force by the monkey's circular movement.

Weight of monkey = 9.5 * 9.81 = 93.2 N

Tension in monkey's arm = Weight + centrifugal force

Tension in monkey's arm = 93.2 + 61.31

Tension in monkey's arm = 154.51 N

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz

d

explanation:

v=uf/(u-f)

= 5.10/(5-10) convex lens has positive focal length

=50/-5

=-10 cm (formed at other side)