A proton, with mass 1.67 x 10-27 kg and charge +1.6 x 10-19 C, is sent with velocity 7.1 x 104 m/s in the +x direction into a region where there is a uniform electric field of magnitude 730 V/m in the +y direction. Assume that the magnetic field has no x-component and neglect gravitational effects. What is the magnitude and direction of the uniform magnetic field in the region, if the proton is to pass through undeflected?What I did was qE=qvB; B=E/V = .010282T but this was incorrect.

colorectal cancer may also develop from areas of abnormal cells in the lining of the colon or rectum. this area of abnormal cells is called dysplasia and is more commonly seen in people with certain inflammatory diseases of the bowel such as crohn's disease or ulcerative colitis.

the displacement produced by the body.  

the amount of force subjected to the body.  

the angle between the direction of force and displacement

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer