Two identical rifles are shot at the same time, and the sound intensity level is 64.7 dB. What would be the sound intensity level if only one rifle were shot

61.7 dB

Explanation:

The sound intensity of Rifle can be calculated using this formula

I ( sound intensity ) = 10 * log ( I / IO) equation 1

where I = power/area

I = 64.7 dB

hence equation 1 becomes

64.7 = 10* log ( I / IO ) equation 2

note the sound intensity was produced by 2 identical rifle hence equation 2 will become

64.7 = 10 * log ( 2P / PO ) equation 3

for a single rifle (X) equation 3 becomes

= 64.7 - 10* log (2) = 64.7 - 10*0.30 = 64.7 - 3

= 61.7 dB

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answer: at 24 february, 2014 the population gets twice of its initial population.

explanation:

since we have given that

the population for alpha city, t years after january 1, 2004 is given as

first we find out the initial population, i.e. t=0,

so, our quadratic equation becomes,

according to question, we have said that if the population has twice its initial population, then it becomes

so, time taken to reach this above mentioned population is given by

now, we know that time can't be negative so, we take t=9.149 years.

hence, at 24 february, 2014 the population gets twice of its initial population.