This problem has been solved! See the answer A kayaker paddles with a power output of 60.0 W to maintain a steady speed of 1.40 m/s a.)Calculate the resistive force exerted by the water on the kayak. b.) If the kayaker doubles her power output, and the resistive force due to the water remains the same, by what factor does the kayaker's speed change?

a) Resistive force = 42.9 N

b) The speed doubles!!

Explanation:

Power = (Energy/time) = (F.d/t) = F.v

a) P = F.v

P = 60.0 W

F = ?

v = 1.40 m/s

60 = F (1.4)

F = (60/1.4)

F = 42.9 N

b) If power doubles, P = 120.0 W and F stays the same, F = 42.9 N

P = F.v

v = (P/F)

v = (120/42.9)

v = 2.80 m/s.

The speed doubles.

here we know that ball will drop down by total distance 3.2 m

so here we know that

now using kinematics

now in the same time it will cover horizontal distance of 0.75 m

so speed of the ball will be