A50,000 kg locomotive is traveling at 10 m/s when its engine and brakes both fail. how far will the locomotive roll before it comes to a stop? assume the track is level.

2551.02 m

Explanation:

Given that, the mass of a locomotive is,

coefficient of friction for steel,

Velocity of the locomotive is

By conservation of energy it can be written as:

Here, E is the energy because of friction.

Now,

Here, m is the mass, v is the velocity of an object.

Now energy of the friction can be written as,

Here, is the coefficient of friction , m is the mass and g is the acceleration due to gravity.

Therefore

Substitute all the variables.

The distance traveled by the locomotive ball before stopping is 2551.02 m

probably not the "magnets"in the magnet, so to speak, are thought to be electrons orbiting in shells. vurrent loops two sides to the loop

grav forces affect all objects magnetic forces affect magnetic objects and electric currents