Given three capacitors, C1C1C_1 = 2.0 μFμF, C2C2C_2 = 1.5 μFμF, and C3C3C_3 = 3.0 μFμF, what arrangement of parallel and series connections with a 12-VV battery will give the minimum voltage drop across the 2.0- μFμF capacitor?

What are the choices?

Answerthe energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.explanationwe define electric potential as the ratio electric potential energy to the charge,    then the following gives us the potential difference,      the formula  may be on your formula sheet.the change in electric potential energy would be the energy that would needed to move it from point a to point b. solving for that, we get    using q = 8.00  × 10⁻¹⁹ c and  δv = 2.00 v, we get    the energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.