What is the power rating of an LED light bulb if 0.50 A flow through it when connected to an 18 V battery?

9 W

Explanation:

The power rating for an Ohmic device (in which the potential difference is directly proportional to the current flowing through it) is given by

where

P is the power

I is the current

V is the potential difference

For the LED light in this problem, we have:

I = 0.50 A is the current flowing

V = 18 V is the potential difference applied

Therefore, the power rating is:

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explanation: