A 20,000 kg railroad car travels down the track at 30 m/s and hits a second stationary railroad car of 10,000 kg. The
cars become coupled and continue traveling. Calculate the final velocity of the cars.

Explanation:

We have , A 20,000 kg railroad car travels down the track at 30 m/s and hits a second stationary railroad car of 10,000 kg. The  cars become coupled and continue traveling. The law of momentum conservation: For a collision occurring between object 1 and object 2 in an isolated system, the total momentum of the two objects before the collision is equal to the total momentum of the two objects after the collision. In this question we will use law of conservation of momentum as :

momentum before collision = momentum after collision

⇒

⇒

⇒

⇒

Therefore, final velocity of both cars are .

1.195000

explanation:

total mass=0.0117+0.0137+0.0881+0.0111

total mass= 0.01172kg

total velocity = 0.283-0.743+0.871-0.799+0.155+0.637+0.301=0.102

momentum=mv=0.1172*0.102=1.195000//

the answer is false. this is because for ice to melt, it requires latent heat of melting. latent heat means heat energy required to change phase without any increase in temperatures. therefore, the ice will take energy from the environment to melt hence atmospheric temperatures will reduce.