A box is given a push so that it slides across the floor. how far will it go given that the How far will it go, given that the coefficient of kinetic friction is 0.13 and the push imparts an initial speed of 3.5 m/s

4.808m

Explanation:

Force is given as:

F = ma

Since the force is a frictional force,

Fr = F

Fr = ma

Frictional force, Fr, is given as:

-umg = ma

a = -ug = -0.13 * 9.8 = -1.274 m/s²

Using one of the equations of motion, we can find the distance:

v² = u² + 2as

Since the box comes to a halt, v = 0m/s:

0 = u² + 2as

s = -u²/2a

s = -(-3.5²)/(2 * 1.274) = 4.808m

i wanna say it’s between b and d, leaning more towards b.

gets less