Two skydivers are holding on to each other while falling straight down at a common terminal speed of 55.9 m/s. Suddenly, they push away from each other. Immediately after separation, the first skydiver (who has a mass of 89.3 kg) has the following velocity components (with "straight down" corresponding to the positive z-axis): V1,x = 7.43 m/s V1,y = 5.75 m/s V1,z = 55.9 m/s What are the x- and y- components of the velocity of the second skydiver, whose mass is 57.7 kg, immediately after separation? V2,x = ? m/s V2,y =? m/s What is the change in kinetic engery of the system? in Joules

10,041.7 J

Explanation:

Using Newton's second law of motion of motion; the linear momentum in each direction will be conserved.

For each direction,

Momentum before collision = momentum after collision

In the x- direction, there was initially no x-component for velocity before collision for the two bodies,

0 = m₁v₁ₓ + m₂v₂ₓ

0 = (89.3)(7.43) + (57.7)(v₂ₓ)

v₂ₓ = (-89.3×7.43)/57.7

v₂ₓ = -11.50 m/s (minus indicating that the motion is in the opposite direction the first diver's motion).

In the y- direction, there was initially no y-component for velocity before collision for the two bodies,

0 = m₁v₁ᵧ + m₂v₂ᵧ

0 = (89.3)(5.75) + (57.7)(v₂ᵧ)

v₂ᵧ = (-89.3×5.75)/57.7

v₂ᵧ = -8.90 m/s (minus indicating that the motion is in the opposite direction the first diver's motion).

And the velocity in the z-axis for both has been given to be 55.9 m/s

Kinetic energy of the system before leaving each other = (1/2)(89.3+57.7)(55.9²) = 229673.535 J

Kinetic energy of skydiver 1 after collision

To do this, we first find the magnitude of the velocity

v₁ = √(7.43² + 5.75² + 55.9²) = 56.684 m/s

Kinetic energy = (1/2)(89.3)(56.684²) = 143463.84 J

Kinetic energy of skydiver 2 after collision

To do this, we first find the magnitude of the velocity

v₂ = √[(-11.50)² + (-8.90)² + 55.9²] = 57.76 m/s

Kinetic energy = (1/2)(57.7)(57.76²) = 96251.39 J

Change in kinetic energy of the system = (final kinetic energy) - (initial kinetic energy)

Change in kinetic energy of the system = 143463.84 + 96251.39 - 229673.535 = 10041.695 J = 10041.7 J

colorectal cancer may also develop from areas of abnormal cells in the lining of the colon or rectum. this area of abnormal cells is called dysplasia and is more commonly seen in people with certain inflammatory diseases of the bowel such as crohn's disease or ulcerative colitis.

i think if it were me i whould divide 300 dide 15

step-by-step explanation: