The electric potential difference across the membrane of a body cell is 0.070 V (higher on the outside than on the inside). The cell membrane is 8.0 x 10-9 m thick. Determine the magnitude and direction of the E field through the cell membrane. Describe any assumptions you made

The electric field is and the ditection is from outer to inner side of the membrane.

Explanation:

We know the electric field () is given by , 'V' being the potential.

In 1-D, it can be written as

where 'd' is the separation of space in between the potential difference is created.

Given, and the thickness of the cell membrane is .

Therefore the created electric field through the cell membrane is

energy can be converted from one form to another, but it cannot be created or destroyed in ordinary chemical or physical means. do not understand what you are asking but hope this