You connect a 9 V battery to a capacitor consisting of two circular plates of radius 0.057 m separated by an air gap of 2.5 mm. What is the charge on the positive plate

Q = 3.254 x 10⁻¹⁰ C.

Explanation:

Given,

Potential, V = 9 V

Radius of circular plat re = 0.057 m

Air gap, s = 2.5 mm

Charge on the positive plate = ?

We know,

Q = C V

and

C = 36.15 x 10⁻¹² F

now,

Q = 36.15 x 10⁻¹² x  9

Q = 3.254 x 10⁻¹⁰ C.

Hence, the charge on the positive plate is equal to Q = 3.254 x 10⁻¹⁰ C.

its c i just checked it

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