Water from a fire hose is directed horizontally against a wall at a rate of 58.1 kg/s and a speed of 43.5 m/s. Calculate the magnitude of the force exerted on the wall (in N), assuming the water's horizontal momentum is reduced to zero.

F = -2527.35 N

Explanation:

Given,

mass per unit time = 58.1 Kg/s

Speed of the water = 43.5 m/s

Final momentum = 0 kg/s

Force = Change in momentum

F = Final momentum - initial momentum

F = 0 - initial momentum

F = -2527.35 N

Hence, the Force exerted is equal to F = -2527.35 N

dang that balls went far

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j