(II) A 1200-kg car moving on a horizontal surface has speed v = 85 km/h when it strikes a horizontal coiled spring and is brought to rest in a distance of 2.2 m. What is the spring stiffness constant of the spring?

k = 138440 N/m

Explanation:

given,

Mass of the car = 1200 Kg

speed of the car = 85 km/h

                            = 85 x 0.278 = 23.63 m/s

KE of the car

Using Spring Energy Formula

Using conservation of energy

    k = 138440 N/m

Spring stiffness constant of the spring is equal to k = 138440 N/m

total distance travelled = 60 miles

total time taken =1.5 hours

average speed = total distance / total time

60 / 1.5

= 40

therefore, average speed = 40 m/h

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