G A steel rod of 0.5 cm diameter and 10 m length is stretched 3 cm. Young’s modulus for this steel is 21 kN/cm2. How much work, in kJ, is required to stretch this rod?

Explanation:

Formula for work using change in volume and Young's modulus is as follows.

        W =

             =

             =

             = 0.124 kJ

Therefore, we can conclude that 0.124 kJ work is required to stretch this rod.

The work done is

Explanation:

Given that,

Length = 10 m

Diameter = 0.5 cm

Young modulus = 21 kN/cm²

Stretched length = 3 cm

We need to calculate the wok done

Using formula of work done

...(I)

We know the deformation is,

Where,

Put the value in the equation (I)

Where,

E = Young modulus

d = diameter

l = length

Put the value into the formula

Hence, The work done is

in simple terms, the principle states that the buoyancy force on an object is equal to the weight of the fluid displaced by the object, or the density of the fluid multiplied by the submerged volume times the gravitational acceleration, g. this is also known as upthrust.