A neon gas tube has Von = 60.0 V and Voff = 30.0 V . What resistor value should you choose to go with a 20.0 μF capacitor and a 120 V battery to make a 30.0 Hz oscillator?

Therefore,

The resistor value , R is 9.4 kΩ.

Explanation:

Given:

A neon gas tube has

Von = 60.0 V and

Voff = 30.0 V

Capacitor, C =  20.0 μF

Battery , E = 120  V

Frequency = f = 30 hz

To Find:

Resistor , R =?

Solution:

Time period of the wave will be only the charging time of the capacitor,the capacitor will be charged to Von from initial voltage Voff  is given by,

Where,

R = Resistance

C =Capacitance

E = Battery in volts

ln = natural Log (Sign)

Substituting the values we get

Therefore,

The resistor value , R is 9.4 kΩ.

answer: a) y=-8x+5

a) m= -8

b) m= -2

c) m= 7

d) m= 6

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