Ou are pushing a 20-kg box along a horizontal floor. Friction acts on the box. When you apply a horizontal force of magnitude 48 N, the box moves at a constant velocity. What is the magnitude of the frictional force on the box?

The magnitude of the frictional force is 48.02 N

Explanation:

Mass of box = 20 kg

Weight of the box (Normal reaction) = mass × acceleration due to gravity = 20 ×9.8 = 196 N

Horizontal force applied = 48 N

Coefficient of friction = horizontal force ÷ normal reaction = 48 ÷ 196 = 0.245

Frictional force = coefficient of friction × normal reaction = 0.245 × 196 N = 48.02 N

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