5. An undisturbed soil sample has a wet density of 2.5 Mg/m3 when the water content is 25%. The specific gravity of the soil particles is 2.7. Determine the submerged effective density.

The submerged effective density is 86.93 kN/m³ or 8.693 Mg/m³

Explanation:

Given;

wet density of soil sample = 2.5 Mg/m³ = 25 kN/m³

Specific gravity of solid particle = 2.7

The dry unit weight of soil;

for undisturbed state, the volume of the soil is;

Submerged effective density is given as;

density of water (ρw) = 2.7 x 25 kN/m³ = 67.5 kN/m³, substitute this in the above equation;

Therefore, the submerged effective density is 86.93 kN/m³ or 8.693 Mg/m³

since you're a real machine, your ama is always less than your ima, because you can never totally eliminate friction.

answer: i'm not sure which is which for i get confused on it all the time but i can tell you that the answer lies with the convex and concave devices. i hope this you. have a good day and best of luck to you!

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