Water vapor enters a turbine operating at steady state at 500°C, 40 bar, with a velocity of 200 m/s, and expands adiabatically to the exit, where it is saturated vapor at 0.8 bar, with a velocity of 150 m/s and a volumetric flow rate of 20 m3 /s. Determine the power developed by the turbine, in kW.

The power developed by the turbine is 7553.8 kW

Explanation:

First we determine the mass flow rate of steam.

given volumetric flow rate as 20 m³ /s

from steam table, density of steam at 0.8 bar = 2.087 kg/m³

Based on energy equation and considering adiabatic flow;

given;

V₁ = 200 m/s,  V₂ = 150 m/s

from steam table, at saturated vapor pressure of 0.8 bar, h₂ = 2665.8 kJ/kg, also at vapor pressure of 40 bar and 500°C, h₁ = 3445.3 kJ/kg

Therefore, the power developed by the turbine is 7553.8 kW

ice to water 1 water to vapour 2 latent heat

i would like to make dinner for my mom, dad, and sister