A 35-N bucket of water is lifted vertically 3.0 m and then returned to its original position. How much work did gravity do on the bucket during this process?

0 J

Explanation:

From the question, let us assume that a positive work was done in lifting the bucket down and a negative work was done in lifting the bucket up.

Going up

W = -Fd Equation 1

Where W = work done,  F = Force needed to lift the bucket, d = distance

Given: F = 35 N, d = 3.0 m

Substitute into equation 1

F = -35(3.0)

F = -105 N.

Coming Down

W = Fd

Given: F = 35 N, d = 3.0 m

W = 35(3.0)

W = 105 N.

During the process (going up and coming down)

ΔW = -150+105

ΔW = 0 J

Hence the work done  by gravity during the process = 0 J

i'm on my way to history not a mistory.

b. false

explanation:

suppose a rock in free fall is dropped off a cliff. after falling for 5 seconds, its speed would not be 100 m/s.