The frequency of the harmonics following a fairly simple pattern, as described in the text. If the frequency of the fundamental (n=1) harmonic is 70.0 Hz, what is the frequency of the second harmonic(n=2)?

f2 = 140 Hz

Explanation:

let fundamental frequency is f1 = 70.0 Hz

formula for finding the higher frequency when fundamental frequency is known

fn = n f1          (where f1 is fundamental frequency and n = 1,2,3,4,5)

for the second frequency n=2

f2 = 2 × 70.0 Hz

f2 = 140 Hz

-4 on

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2