A bullet is accelerated down the barrel of a gun by hot gases produced in the combustion of gun powder. What is the average force (in N) exerted on a 0.0500 kg bullet to accelerate it to a speed of 625 m/s in a time of 1.10 ms (milliseconds)

28409.1 N

Explanation:

Force: This can be defined as the product of mass and acceleration. The S.I unit of force is Newton(N).

From the question,

F = maEquation 1

Where F = force exerted on the bullet, m = mass of the bullet, a = acceleration of the bullet.

But,

a = v/t Equation 2

Where v = velocity,t = time.

Substitute equation 2 into equation 1

F = m(v/t) Equation 3

Given: m = 0.05 kg, v = 625 m/s, t = 1.1 ms = 0.0011 s.

Substitute into equation 3

F = 0.05(625)/0.0011

F = 28409.1 N

where are the vectors ?

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .