The gravitational force of a star on an orbiting planet 1 is F1. Planet 2, which is three times as massive as planet 1 and orbits at twice the distance from the star, experiences gravitational force F2.?

F_1 / F_2 = 4 / 3

Explanation:

Given:

- Planet 1:-

            mass = m

            orbit = R

- Planet 2:-

           mass = 3m

           orbit = 2R

- Mass of star = M

Find:

- The ratio of gravitational forces F_1 / F_2?

Solution:

- The force of attraction between star and planet 1 is given by:

                                 F_1 = G*(m)*(M) / R^2

- The force of attraction between star and planet 2 is given by:

                                 F_2 = G*(3m)*(M) / (2R)^2

- the ratio of the two forces is:

                                F_1 / F_2 = [G*(m)*(M) / R^2] / [G*(3m)*(M) / (2R)^2 ]

                                F_1 / F_2 = 4 / 3

answer: the direction of the wind is expressed as the direction from which the wind is blowing. for example, easterly winds blow from east to west, while westerly winds blow from west to east.

explanation:

e) none of the above answers are correct