When point charges q1 = +7.9 μC and q2 = +6.0 μC are brought near each other, each experiences a repulsive force of magnitude 0.75 N. Determine the distance between the charges.

0.754m

Explanation:

F=kq1q2/r^2

R^2= kq1q2/f

R^2= 9*10^9*7.9*10^-6*6.0*10^-6/0.75

R^2= 9*7.9*6*10^-3/0.75

R^2=0.4266/0.75

R^2=0.5688

R=√0.5688

R=0.754m

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i believe the answer is a