A force of 250 newtons stretches a spring 30 centimeters. How much work is done in stretching the spring from 20 centimeters to 50 centimeters?

Work done = 87.5 J

Explanation:

Given:

Force required to stretch the spring (F) = 250 N

Extension of the spring (x) = 30 cm = 0.30 m     [1 cm = 0.01 m]

So, spring constant (k) of the spring is given as:

Also given:

Initial length of the spring (x₁) = 20 cm = 0.20 m

Final length of the spring (x₂) = 50 cm = 0.50 m

Now, work done in stretching the spring from an initial length (x₁) to final length (x₂) is given as:

Plug in the given values and solve for 'W. This gives,

Therefore, work is done in stretching the spring from 20 centimeters to 50 centimeters is 87.5 J

unbalanced force

explanation:

dec 23, 2016 - a load of bricks weighing 680 n a distance of 10 m across a parking lot. if if the worker pushes the cart with a constant force of 209 n, what work= force x distance = 220 n x 10 m = 2200 n.m = 2200 j i don't know where the person got it from, but the initial part, work= force x distance me.