The electron current in a horizontal metal wire is 7.4 × 1018 electrons/s, and the electrons are moving to the left. What are the magnitude and direction of the conventional current?

The magnitude and direction of the conventional current is then 1.186 Amps moving to the left direction

Explanation:

To answer the question, it should be noted that the direction of conventional current is in the opposite direction of the flow of electrons. Therefore, the direction of flow of conventional current will be to the right

The magnitude of the electric current is equal to the rate of flow of the electrons or the time it takes for the electrons to flow past a section of the wire. Therefore the magnitude is that of the 7.4 × 1018 electrons/s

However the unit of the electricity = ampere which is = coulombs/seconds

The 7.4 × 1018 electrons carry

7.4 × 10¹⁸×1.60217662 × 10⁻¹⁹ coulombs = 1.1856106988 coulombs

Therefore the magnitude of electric current = 1.186 coulombs/Seconds

= 1.186 Amps

the expression 15n + 2(3p) represents the amount isaiah spent buying gasoline and snacks, where n represents the price of each gallon of gasoline and p represents the cost of each snack that he bought. which statement is true about the amount isaiah spent?