If the dielectric constant is 14.1, calculate the ratio of the charge on the capacitor with the dielectric after it is inserted as compared with the initial charge.

Explanation:

Capacitance is defined as the charge divided in voltage.

Introducing a dielectric into a parallel plate capacitor decreases its electric field. Therefore, the voltage decreases, as follows:

Where k is the dielectric constant and the voltage of the capacitor without a dielectric

The capacitance with a dielectric between the capacitor plates is given by:

Where k is the dielectric constant and the capacitance of the capacitor without a dielectric. So, we have:

Therefore, a capacitor with a dielectric stores the same charge as one without a dielectric.