In a particular television picture tube, the measured beam current is 23.3 µA . How many electrons strike the tube screen every 28 s ? The fundamental charge is 1.602 × 10−19 C. Answer in units of electrons.

Explanation:

Given that

Beam current (i)=23.3µA

And the time to strike(t)=28s

Also, a fundamental charge e=1.602×10^-19C

Then, the charge quantity is given as,

q=it

Then, q=23.3×10^-6×28

q=6.524×10^-4C

Also, the number of electron N is given as

q=Ne

Therefore, N=q/e

So, N=6.524×10-4/1.602×10^-19

N=4.072×10^15

There are 4.072×10^15 electrons strike the tube screen every 28 s.

we need some answer choices, or something like that

explanation: