A lead block drops its temperature by 5.90 degrees celsius when 427 J of heat are removed from it. what is the mass of the block?(unit=kg) IM GIVING 30 POINTS FOR THE CORRECT ANSWER

577g

Explanation:

Given parameters:

Temperature change = 5.9°C

Amount of heat lost = 427J

Unknown:

Mass of the block = ?

Solution:

The heat capacity of a body is the amount of heat required to change the temperature of that body by 1°C.

                H =  m c Ф

  H is the heat capacity

 m  is the mass of the block

  c is the specific heat capacity

   Ф is the temperature change

Specific heat capacity of lead is 0.126J/g°C

   m = H / m Ф

   m =  = 577g

Mass of the lead block is 577g

the higher the current the higher the mag field around it the higher the influence on the compass

the displacement produced by the body.  

the amount of force subjected to the body.  

the angle between the direction of force and displacement