A solenoid used to produce magnetic fields for research purposes is 2.2 mm long, with an inner radius of 25 cmcm and 1300 turns of wire. When running, the solenoid produced a field of 1.5 TT in the center.

Incomplete question as we have not told which quantity to find.So the complete question is here

A solenoid used to produce magnetic fields for research purposes is 2.2 mm long, with an inner radius of 25 cmcm and 1300 turns of wire. When running, the solenoid produced a field of 1.5 TT in the center.Given this, how large a current does it carry?

Explanation:

Magnetic field B=1.5 T

Length L=2.2mm =0.0022m

Number of turns N=1300 turns

To find

Current I

Solution

From the magnetic at the center of loop we know that:

Substitute the given values

inverse v=i*r

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