Bob the velociraptor chases Baby Yoda ( mass of 10kg) down a hill. At the bottom baby Yoda has a velocity of 15 m/s . What was baby yoda's kinetic energy at the bottom of the hill?

K. E = 1125 J or 1.125KJ

Explanation:

Mass (m) =10kg

Velocity (v) = 15m/s

Kinetic energy = ½ mv²

K. E = ½ × 10 × 15²

K. E = 5 × 225

K. E = 1125Joules

K. E = 1125 J or 1.125KJ

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1125joules

Explanation:

Mass(m)=10kg velocity(v)=15m/s

Kinetic energy=mv^2/2

Kinetic energy =(10 x 15^2)/2

Kinetic energy =(10 x 225)/2

Kinetic energy =2250/2

Kinetic energy =1125joules

see earlier answer

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