The velocity of a sky diver t seconds after jumping is given by v(t) = 80(1 − e−0.2t). After how many seconds is the velocity 65 ft/s? (Round your answer to the nearest whole number.)

8 seconds

Explanation:

Given:

The velocity of the sky diver 't' seconds after jumping is given as:

The velocity is given as,

So, in order to find the time required to reach the above given velocity, we plug in 65 for 'v' in the above equation and solve for time 't'. This gives,

Therefore, the time taken to reach a velocity of 65 ft/s is nearly 8 seconds.

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